What is 3log2 x-(log2 3-log2 (x+4)) written as a single logarithm?

Answer:log_2((x^4+4x^3)/3)Step-by-step explanation:First step would be distribute that - into the ( )3log_2(x)-log_2(3)+log_2(x+4)Now take care of coefficients of the logs... bring them up as powers of the insidelog_2(x^3)-log_2(3)+log_2(x+4)or+log_2(x^3)-log_2(3)+log_2(x+4)Now for the product and quotient rule! If it has a + in front of it, it will go on top. If it has a - in front of it, it will go on bottom.Like this:log_2 (x^3(x+4)/3)orlog_2((x^4+4x^3)/3)So inside that log base 2 thing the top is x^4+4x^3and that bottom is 3