The height of a cone is two times its base diameter. What is the volume of the cone in terms of its base radius r?A.V=[tex]\frac{2}{3}\\[/tex](pi)(r²)B.V=[tex]\frac{4}{3}\\[/tex](pi)(r³)C.V=[tex]\frac{1}{3}\\[/tex](pi)(r³)D.V=[tex]\frac{1}{3}\\[/tex](pi)(r²)
Accepted Solution
A:
Answer:BStep-by-step explanation:Assume the radius is r so the diameter is 2rHeight=2*d=2(2r)=4r since the diameter is twice the radiusVolume of cone=1/3 * pi*r^2*h = 1/3 * pi*r^2*(4r) =4/3 *pi *r^3So B