Consider the function f(x)=(x-9)/(x^3-81x)Find the vertical asymptote(s) of f(x)
Accepted Solution
A:
Well, here's a harder one Basically, to find a vertical asymptote, we set the denominator to 0. Like this: x^3 - 81x = 0 Then we solve for x. x(x^2 - 81) = 0 x(x+9)(x-9) = 0 x = 0, 9, -9 There are vertical asymptotes at x = 0, x = 9, and x = -9.